Question

Prove that
1+ sec A
sec A
1 -cos A​

Answer 1

hence proved first tell me your real name after that i will tell

Answer 2

Answer:

ok

Step-by-step explanation:

Given Equation is (1 + tan^2A/(1 + secA)).

We know that tan^2A + 1 = sec^2A.

tan^2A = sec^2A - 1.

1 + \frac{sec^2A - 1}{1 + secA}1+

1+secA

sec

2

A−1

1 + \frac{(secA + 1)(secA - 1)}{1 + secA}1+

1+secA

(secA+1)(secA−1)

1 + secA - 11+secA−1

secA.

LHS = RHS.

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