prove that 1+ sec a / sec a = sin^2 a/ 1_ cos a
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Answer:
as we know sec A = 1/ Cos A
By putting the value in L.H.S we get 1+ cos A
again R.H.S
sin^2 A / 1- Cos A
= 1- Cos ^2 A / 1 - Cos A
= (1- Cos A ) ( 1+ Cos A ) / 1- Cos A
= 1+ Cos A
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