Prove that 1/ (sec A – tan A) = sec A + tan A
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Step-by-step explanation:
1/Sec theta - Tan theta = Sec theta + Tan theta
We have,
LHS = 1/Sec theta - Tan theta
1/Sec theta - Tan theta × (Sec theta+Tan theta)/(Sec theta+Tan theta)
=> (Sec theta+Tan theta)/(Sec²thta-Tan²theta)
=> Sec theta + Tan theta = RHS
Hence,proved.
LHS = RHS.....PROVED.....
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