Prove that
1/sec theta + tan theta = sec theta - tan theta
Answers
Answered by
0
Answer:
We have,
LHS =
secθ−tanθ
1
⇒ LHS =
secθ−tanθ
1
×
secθ+tanθ
secθ+tanθ
⇒ LHS =
sec
2
θ−tan
2
θ
secθ+tanθ
=
1
secθ+tanθ
[∵sec
2
θ−tan
2
θ=1]
⇒ LHS = secθ+tanθ=RHS
Answered by
0
Similar questions