Math, asked by jayparkash, 1 year ago

prove that 1/sec theta+tan theta =sec theta -tan theta.
please answer in full step

Answers

Answered by mysticd
12

Answer:

\frac{1}{sec \theta+tan \theta}= sec\theta-tan\theta

Step-by-step explanation:

LHS = \frac{1}{sec\theta+tan\theta}\\=\frac{sec^{2}\theta-tan^{2}\theta}{(sec\theta+tan\theta)}

 By \: trigonometric \: identity :\\</p><p>\boxed { sec^{2}\theta - tan^{2}\theta }

 = \frac{(sec\theta+tan\theta)(sec\theta-tan\theta)}{(sec\theta+tan\theta)}

/* By algebraic identity:

- = ( a + b )( a - b ) */

= sec\theta-tan\theta\\=RHS

Therefore,.

\frac{1}{sec\theta+tan\theta}= sec\theta-tan\theta

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Answered by rajanileash991
0

Answer:

LHS=ee33hfgfftyyy is a very good

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