prove that 1-sec8alpa/1-sec4alpa=tan8alpha/tan2alpha
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sorry but don't know the answer of this question....
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Given, (sec8A - 1) / (sec4A - 1)
= (1/cos8A) - 1) / (1/cos4A) - 1
= (1 - cos8A)/cos8A) / (1 - cos4A) / cos4A)
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