Question

Prove that
1+secA/secA=sin^2A/1-cosA​

Answer 1

Answer:

(1 + sec A)/ sec A = sin^2 A/(1 - cos A)

Here LHS = cos A +1.

RHS = (1-cos^2 A)/(1 - cos A)

= (1 + cos A) *(1 - cos A) /(1 - cos A)

= cos A +1 = LHS

Proved.

Answer 2

Answer:

Step-by-step explanatio

Note:

1/secA= cosA

And. Sin^2A= 1-cos^2A