Prove that 1+secA/secA = sin²A/(1-cosA)
Answers
Answered by
1
Answer:
Step-by-step explanation:
To prove :
secA
1+secA
=
1−cosA
sec
12
A
LHS
secA
1+secA
=
cosA
1
1+
cosA
1
=
cosA
1
cosA
cosA+1
=
cosA
cosA+1
×
1
cosA
=1+cosA
=1+cosA×
1−cosA
1−cosA
=
1−cosA
(1)
2
−(cosA)
2
=
1−cosA
1−cos
2
A
=
1−cosA
sin
2
A
=RHS
To prove :
secA
1+secA
=
1−cosA
sec
12
A
LHS
secA
1+secA
=
cosA
1
1+
cosA
1
=
cosA
1
cosA
cosA+1
=
cosA
cosA+1
×
1
cosA
=1+cosA
=1+cosA×
1−cosA
1−cosA
=
1−cosA
(1)
2
−(cosA)
2
=
1−cosA
1−cos
2
A
=
1−cosA
sin
2
A
=RHS
Answered by
19
Step-by-step explanation:
To Prove:-
Proof:-
By rationalising :-
= RHS
LHS = RHS
Hence Proved
Similar questions