Math, asked by shanmuk845, 2 months ago

prove that 1+secA÷secA=sin2A÷1-cosA

Answers

Answered by anbukingky

3

Step-by-step explanation:

To prove : secA1+secA=1−cosAsec12A

LHS secA1+secA=cosA11+cosA1

=cosA1cosAcosA+1

=cosAcosA+1×1cosA

=1+cosA

=1+cosA×1−cosA1−cosA

=1−cosA(1)2−(cosA)2

=1−cosA1−cos2A

=1−cosAsin

Answered by harivzg

2

Step-by-step explanation:

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