prove that 1+secA/ secA = sinSquareA / 1-cosA
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1+secA/secA=sin²A/1-cosA
LHS
=1+secA/secA
=1+1/cosA/1+1/cosA
=(cosA+1/cosA)cosA
=(1+cosA)
Multiply and divide with (1 – cosA)
=(1+cosA)*(1-cosA)/(1-cosA)
=(1-cos²A)/(1-cosA)
=sin²A/1-cosA
RHS
=sin²A / 1-cosA
hence Proved
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