Math, asked by saiprakash62, 1 year ago

prove that 1+secA/ secA = sinSquareA / 1-cosA

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Answered by arshad4286

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Hope u can understand ...

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Answered by aryansharma96651

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1+secA/secA=sin²A/1-cosA

LHS

=1+secA/secA

=1+1/cosA/1+1/cosA

=(cosA+1/cosA)cosA

=(1+cosA)

Multiply and divide with (1 – cosA)

=(1+cosA)*(1-cosA)/(1-cosA)

=(1-cos²A)/(1-cosA)

=sin²A/1-cosA

RHS

=sin²A / 1-cosA

hence Proved

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