Prove that 1/secA-tanA-1/cosA=1/secA-1/secA+tanA
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Step-by-step explanation:
from LHS
1/secA-tanA-1/cosA
=secA+tanA/(secA-tanA)(secA+tanA)-1/cosA
=(secA+tanA/sec²A-tan²A)-secA
=secA+tanA-secA
=tanA
Now from RHS
secA-1/secA+tanA
=secA-(secA-tanA/sec²A-tan²A)
=secA-(secA-tanA)
=tanA
so,LHS=RHS
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