Math, asked by Rushikesh7374, 9 months ago

prove that 1/secA-tanA -1/cosA=tanA

Answers

Answered by Tragicgirl773

4

Answers

LHS=1/secA+tanA

1/secA+tanA*secA-tanA/secA-tanA

secA-tanA/sec^2A-tan^2A

secA-tanA/1

SecA-tanA

LHS=RHS

Hope this helps!

Answered by gnanasekarsathya546

1

Step-by-step explanation:

(1/1/cosA-sinA/CosA)-1/cosA=tanA

(1/1-sinA/cosA)-1/cosA=tanA

(cosA/1-sinA)-1//cosA=tanA

cos^2A-1-sinA/(1-sinA)cosA=tanA

sin^2A-sinA/sinA-1(cosA)=tanA

sinA(sinA-1)/(sinA-1)cosA=tanA

sinA/cosA=tanA

tanA=tanA

Hence proved

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