Question

prove that 1/secA-tanA -1/cosA=tanA​​​

Answer 1

Step-by-step explanation:

Given LHS = 

On rationalizing we get,









secA+tanA.

LHS = RHS.

Answer 2

Step-by-step explanation:

(secA+tanA)

1

−

cosA

1

=

cosA

1

−

(secA−tanA)

1

∴

(secA+tanA)

1

−

cosA

1

−

cosA

1

+

(secA−tanA)

1

=0

LHS=

sec

2

A−tan

2

A

secA−tanA+secA+tanA

−

cosA

2

=2secA−

cosA

2

=

cosA

2

−

cosA

2

=0

=RHS