Question

prove that 1+seca-tana/1+seca+tana =1-sina/cosa​

Answer 1

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$\displaystyle \: \frac{ (1+sec A - tan A \: )}{( 1+sec A +tan A \: )}$

$= \displaystyle \: \frac{ (sec A - tan A + 1 \: )}{( sec A +tan A + 1\: )}$

$= \displaystyle \: \frac{ (sec A - tan A + sec²A- tan²A}{ ( secA +tan A + 1\: )}$

$= \: \frac{[(sec A - tan A) + (sec A+tan A) (sec A - tan A)}{ ( sec A +tan A + 1\: )}$

$= \displaystyle \: \frac{(secA - tan A)( sec A +tan A + 1\: ) }{( sec A +tan A + 1\: )}$

$\displaystyle \:= (sec A - tan A\: )$

$\displaystyle \: = \frac{( 1 - sin A ) }{cos A}$

Answer 2

Answer:

1-SIN A / COS A IS THE CORRECT ANSWER..

Step-by-step explanation:

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