Question

Prove that:
1 + secA - tanA / 1 + secA + tanA = 1- sinA / cosA

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Answer 1

Answer:

(1+secA-tanA)/(1+secA+tanA)= (1-sinA)/cosA.

L.H.S.

={(sec^2A-tan^2A)+(secA-tanA)}/(1+secA+tanA).

={(secA-tanA).(secA+tanA)+(secA-tanA)}/(1+secA+tanA).

=(secA-tanA).(secA+tanA+1)/(1+secA+tanA).

=secA-tanA.

=1/cosA-sinA/cosA.

=(1-sinA)/cosA. Proved.

Step-by-step explanation:

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Answer 2

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