Math, asked by ADAMSHARIEFF, 1 year ago

Prove that 1÷secA+tanA=secA-tanA

Answers

Answered by Vinayak333

In LHS
=1÷(secA+tanA)
rationalising
=1×(secA-tanA)/(secA+tanA)×(secA-tanA)
=secA-tanA/sec²A-tan²A
we knows the trigonometry identity that is
1+tan²A=sec²A
so, 1=sec²A-tan²A
Now,
=secA-tanA/1
that is secA-tanA=secA-tanA
LHS=RHS
Hence proved
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ADAMSHARIEFF: sure will

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Answered by Aasiyaalmani123

solution:
taking l.h.s
BY RATIONALIZING

  1 secA - tanA
----------------------- * -----------------------
   secA + tan A SECA - TanA

secA - tan A
-------------------------
[secA]^2 - [tanA]^2

as sec2 - tan2 = 1

secA-tanA
----------------
   1

l.h.s = r.h.s.......
hope u like it

Aasiyaalmani123: if u like it mark it as brainlist i need it

ADAMSHARIEFF: im sorry im done marking vinayak as the branliest but thanks for answering

Aasiyaalmani123: its fine

Aasiyaalmani123: delete my answer

ADAMSHARIEFF: why

Aasiyaalmani123: leave it

ADAMSHARIEFF: ok

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