Question

prove that√ 1-sin/1+sin=1sec+tan with process​

Answer 1

Step-by-step explanation:

√1-sin/1+sin

=√(1-sin/1+sin)×(1-sin/1-sin)

=√(1-sin)²/1-sin²

=√(1-sin)²/cos²

=1-sin/cos

=1/cos-sin/cos

=sec-tan