Prove that
√(1+sin∅)/(1-sin∅) = tan∅+sec∅
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Answered by
13
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Answer : Refer Attached Image
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Hope it helped! ☺
Nice Question! ♥
======================================
Answer : Refer Attached Image
======================================
Hope it helped! ☺
Attachments:

Answered by
7
here I am writing this symbol ∅ as a. Since It is difficult for me to write always.
Given RHS is tan a + Seca.
On squaring, we get
(Seca + tana)^2
sec^2a + tan^2a + 2secatana





Therefore,

Hope this helps!
Given RHS is tan a + Seca.
On squaring, we get
(Seca + tana)^2
sec^2a + tan^2a + 2secatana
Therefore,
Hope this helps!
siddhartharao77:
If you find any mistakes, tell me i will correct.
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