prove that 1/sin 10power4 - root3/cos10power4 = 4
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Step-by-step explanation:
Answer
LHS :
sin10o1−cos10o3
=2[2sin10o1−2cos10o3]
=2[sin10osin30o−cos10ocos30o]
=2[sin10ocos10osin30ocos10o−cos30osin10o]
=2[sin10ocos10osin20o]
=2×2[sin10ocos10osin10o
4=RHS
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