Question

Prove that √1-sin^2 (90°- theta) + √4-4sin^2(90°-theta) = 3 sintheta

Answer 1

Answer:

Step-by-step explanation:

√1-sin²(90°-theta) + √4-4 sin²(90°-theta) = 3 sin theta

LHS

√1-cos²theta + √4-4 cos²theta         {sin²(90°- theta) = cos² theta}

√sin²theta + √4 sin²theta

sin theta + 2 sin theta

3 sin theta = RHS

Answer 2

Answer:

3 sin theta = RHS

Hope it will be helpful ✌️