Math, asked by king771, 1 year ago

prove that: ^[1-sin^2A(90-A)] + ^[4-4sin^2(90-A)] = 3sinA

Answers

Answered by mysticd
1
Hi ,

[1 - sin² ( 90 - A )] + [ 4 - 4sin²(90 - A )]

= 3sinA

LHS =[1-sin²(90-A)]+[4-4sin²(90-A)]

= [ 1 - cos² A ] + [ 4 - 4cos²A ]

= sin² A + 4( 1 - cos² A )

= Sin² A + 4sin² A

= 5sin²A

Plz , check the answer .

I hope this helps you.

: )
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