Question

Prove that:

1/sin^2theta +1/cos^2theta+1/sec^2theta+1/cosec^2theta=2​

Answer 1

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➣ 1/sin^2theta +1/cos^2theta+1/sec^2theta+1/cosec^2theta=2

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➣ cos²A + sin²A = 1

➣ 1 + tan²A = sec²A

➣ 1 + cot²A = cosec²A