Question

Prove that
(1) sin’30° + sin45° + sin60 degree=
(ii) tanʼ30° + tan+45° + tan60° = 4 1/3 mixed fraction

Answer 1

Answer:

proved it but don't know how to send

Answer 2

sin30=1/2 sin45=√2/2 sin60=√3/2

tan30=1/√3 tan45=1 tan60=√3

so (i) is (1+√2+√3)/2 and (ii) is 4+ 1/√3