Prove that √1+sin a / 1- sin a = sec a + tan a
Answers
Answered by
2
Step-by-step explanation:
(1−sinA)
(1+sinA)
×
(1+sinA)
(1+sinA)
=
1−sin
2
A
(1+sinA)
2
=
cos
2
A
(1+sinA)
2
=
cosA
1+sinA
=
cosA
1
+
cosA
sinA
=secA+tanA
Hence proved.
Answered by
0
Answer:
CHECK YOUR QUESTION AGAIN U HAVE WRITTEN IT WRONG
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