Math, asked by saswatacharya536, 5 months ago

prove that √(1+sin A/1-sin A)=secA+tanA​

Answers

Answered by jainanshita441
3

Step-by-step explanation:

(1 + sin∅) × √(1 + sin∅)/√(1 - sin∅)×√(1 +sin∅) = √(1 + sin∅)²/√(1 -sin²∅) = ( 1 + sin∅)/√cos²∅ = (1 + sin∅)/cos∅ = 1/cos∅ + ...

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