Question

prove that 1-sin A upon 1+si A = ( sec A - tan A ) 2​

Answer 1

Answer:

√(1+sinA)/(1-sinA) × (1+sinA)/(1+sinA) = √(1+sinA)^2/1-sin^2A

√(1+sinA)^2/cos^2A =1+sinA)cosA

1/cosA + sinA/cosA= secA+tanA

Hence proved

Answer 2

Answer:

l think in rhs after (secA-tanA) you tried to write square of this