Prove that 1-sin teta/1+sin teta = (sec teta -tan teta)hole square
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lhs=(secФ-tanФ)² =(1/cosФ-sinФ/cosФ)² =(1-sinФ)²/(cosФ)² we know that sin²Ф+cos²Ф=1 cos²Ф=1-sin²Ф =1²-sin²Ф (1-sinФ)²/1²-sinФ =(1-sinФ) (1-sinФ)/(1+sinФ) (1-sinФ) =1-sinФ/1+sinФ
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