Question

prove that:√1+sin there/1-sin theta=sec theta+tan theta=?
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Answer 1

Step-by-step explanation:

1. √1+sin theta/1-sin thera
2. rationalise the denominator

• √1+sin theta/1-sin theta×√1+sin theta/1+sin theta
• √(1+sin theta)^2/1-sin^2theta
• √(1+sin theta)^2/cos^2 theta
• square cancel by underroot
• 1+sin theta/cos theta
• 1/cos theta+sin theta/cos theta
• sec theta+tan theta
• hence proved