prove that 1+sin theta/1-sin theta = (1+sin theta/cos theta ) ^2
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Answered by
4
Answer:
1+sin θ / 1-sin θ
Take conjugate,
=1+sinθ / 1-sinθ* 1+sin θ / 1+sinθ
=1+sinθ * 1+sinθ/ 1-sinθ * 1+sinθ
= (1+ sinθ)² / (1-sin²θ)
=(1+sinθ)² / cos²θ
=(1+sinθ / cosθ)².
Hence, Proved.
I hope, my answer helped you.
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