Question

Prove that 1+sin theta/1-sin theta=(sec theta+tan theta)^2

Answer 1

Step-by-step explanation:

(secθ+tanθ)²

=(1+sinθ/cosθ)²

=(1+sinθ)/cos²θ

=(1+sinθ)²/(1-sin²θ)

=(1+sinθ)/(1-sinθ)