Prove that 1+sin theta/1-sin theta=(sec theta+tan theta)^2
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Step-by-step explanation:
(secθ+tanθ)²
=(1+sinθ/cosθ)²
=(1+sinθ)/cos²θ
=(1+sinθ)²/(1-sin²θ)
=(1+sinθ)/(1-sinθ)
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