Math, asked by ayaanbhai05, 4 months ago

Prove that (1-sin²) Sec² =1​

Answers

Answered by kirtansoni09
1

This is your answer

Step-by-step explanation:

(1 -  {sin}^{2} ) {sec}^{2}

 {cos}^{2}  \times  {sec}^{2}

[By formula sin^2+cos^2 = 1 then,cos^2 = 1-sin^2]

 {cos}^{2}  \times  \frac{1 }{ {cos}^{2} }

[As,secx = 1/cosx then,sec^2x = 1/cos^2x ]

= 1

Hence proved

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