prove that : ( 1 - sin2 theta ) sec2 theta =1
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(1- sin^2 theta )sec ^2 theta
=( cos ^ 2 theta ) 1/ cos ^2 theta [[sin ^theta + cos^2 theta =1. and. sec ^2 theta = 1/ cos^2 theta]]
=1
=( cos ^ 2 theta ) 1/ cos ^2 theta [[sin ^theta + cos^2 theta =1. and. sec ^2 theta = 1/ cos^2 theta]]
=1
Answered by
32
Proof for : ( 1 - sin2 theta ) sec2 theta =1 is given as follows
To prove,
we know the trigonometric properties,
Therefore, we have,
LHS:
we know the trigonometric ratios, given by,
= 1
:RHS
Hence the proof.
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