prove that 1+sin2A /cos2A = cosA +sinA/cosA - sinA = tan(22/7 /4 +A)
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tan(45 + A) = [tan45 + tanA]/[1 - tan45tanA] = [1 + tanA]/[1 - tanA]
[1 + sinA/cosA]/[1 - sinA/cosA] = [cosA + sinA]/[cosA - sinA]
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