Prove that:
(1+sin60⁰)/(1-sin60⁰)={(1+cot60⁰)/1-cot60⁰)}²
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Answered by
26
Answer:
LHS = (1-sin60°)/cos60° = (1 - √3/2)/(1/2) = (2-√3)
RHS = (tan60° -1)/(tan60° +1)
=(√3 -1)/(√3 +1)
=(√3-1)(√3-1)/(√3 +1)(√3 -1)
=(√3² +1² -2√3)/(√3²-1)
=( 4-2- √3)/(2)
= 2-√3
LHS = RHS
hence proved
hope it helps
Answered by
36
Answer:
see the attachment , friend.
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