Question

Prove that :
1- sinA / 1+sin A = (sec A — tan A)²

Answer 1

1-sinA/1+sinA=(secA-tanA)²


L.H.S

1-sinA/1+sinA


Rationalising the denominator



1-sinA (1-SinA) /1+sinA(1-SinA)


(1-SinA)²/ 1² -(Sin²A)


(1-SinA)²/ 1 -(Sin²A)




(1-SinA)² /Cos² A


[ 1 -Sin²A = cos²A]


(1-SinA/CosA)²



(1/CosA-SinA/CosA)²


(SecA-tanA)²



L.H S = R H.S


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Hope this will help you.....

Answer 2

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