Question

Prove that √1+sinA/1-sinA = sec A + tan A​

Answer 1

Answer:

root1+sinA/root1−sinA

=root(1+sinA)/root(1−sinA)(1−sinA)2

=rootcos2A(1−sinA)2

=root(secA−tanA)2

=∣secA−tanA∣

Hope it helps you.

Answer 2

Answer:

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