Math, asked by ribckadasari, 11 months ago

Prove that

√1-sinA/1+sinA=secA-tanA

Answers

Answered by sandy1816

0

Step-by-step explanation:

√(1-sinA)/(1+sinA)

=√(1-sinA)²/(1-sin²A)

=√(1-sinA)²/cos²A

=1-sinA/cosA

=secA-tanA

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