Question

prove that (1+sinA)/(1-sinA) = (secA+tanA)^2 ​

Answer 1

Answer:

RHS = (1/cos A + SinA/CosA)^2={ (1+SinA)/CosA}^2

=(1+SinA)^2 / cos^2

=(1+SinA)^2/(1 - sin^2) = (1+sinA)^2 /{(1+sinA)(1-sinA)

(1+sinA)/(1-sinA) = LHS