Prove that :√1+sinA by 1-sinA +√1-sinA by 1+sinA = 2 secA .......pls solve it
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Step-by-step explanation:
√1+sinA/1-sinA+√1-sinA/1+sinA
=√1+sinA/√1-sinA+√1-sinA/√1+sinA
=1+sinA+1-sinA/√1+sinA.√1-sinA
=2/√1-sin²A
=2/cosA
=2secA
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