Math, asked by pb237, 9 months ago

Prove that :√1+sinA by 1-sinA +√1-sinA by 1+sinA = 2 secA .......pls solve it

Answers

Answered by sandy1816

2

Step-by-step explanation:

√1+sinA/1-sinA+√1-sinA/1+sinA

=√1+sinA/√1-sinA+√1-sinA/√1+sinA

=1+sinA+1-sinA/√1+sinA.√1-sinA

=2/√1-sin²A

=2/cosA

=2secA

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