Prove that: (1+sinA-cosA/1+sinA+cosA) = 1-cosA/1+cosA
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not understanding question
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hey you have missed the square at LHS which made question wrong
as it is
[1+SinA-CosA]²/[1+SinA+CosA]² =[1-cosA]/[1+cosA]
and the proof for this is
[1+Sin²A+Cos²A+2SinA-2SinACosA-2CosA]/
[1+Sin²A+Cos²A+2SinA+2SinACosA+2CosA]
[2+2SinA-2SinACosA-2CosA]/
[2+2SinA+2SinACosA+2CosA]
(1+SinA)(1-CosA)/(1+SinA)((1+CosA)
(1-cosA)/(1+CosA)
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