Question

prove that:(1+sina-cosa)^2-(1-sina+cota)^2=4cosa(tana-1)​

Answer 1

Answer:

ANSWER

sinA+cosA−1sinA−cosA+1

=sinA−(1−cosA)sinA+(1−cosA)

=2sin2Acos2A−2sin22A2sin2Acos2A+2sin22A

=cos2A−sin2Acos2A+sin2A

=cot2A+1cot2A−1=cot(4π−2

Answer 2

Answer:

prove that:(1+sina-cosa)^2-(1-sina+cota)^2=4cosa(tana-1)