prove that 1+sinA/cosA + cosA/1+sinA= 2 sec A
Answers
Answered by
0
Step-by-step explanation:
= sin^2A + ( 1 + cosA)^2 / ( 1+ cosA) . sinA
= sin^2A + cos^2A + 2 cosA + 1 / (1+cosA) . sinA
= 2 + 2 cosA / (1+ cosA ) . sinA
= 2 ( 1 + cosA ) / (1+cosA ) . sinA
= 2 / sinA = 2 × 1/ sinA = 2 cosecA
I think your question is wrong .
2 sec theta will be replaced by 2 cosec theta . this is right question.
Similar questions