prove that
1+sinB --------- =(secB+tanB)² 1-SinB
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Answer:
RHS=(secB-tanB)²
=(1/cosB-sinb/cos)²
=(1-sinB)²/cos²B
=(1-sinB)(1-sinB)/(1+sinB)(1-sinB)
=(1-sinB)/(1+sinB)
RHS=LHS
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