Question

Prove that (1−tanθ/1−cotθ)^2=tan^2θ
pls explain

Answer 1

Step-by-step explanation: (1-tanx/1-cosx)^2

= [(cosx-sinx) sinx/(sinx-cosx) cosx] ^2

Taking (-) common from numerator and canceling (sinx - cosx)

=(-sinx/cosx) ^2

=sin^2x/cos^x (since square of - 1 is always positive (+))

=tan^2x