Prove that:
(1 + tan^2 Φ) * cos Φ * cos(90° - Φ) = cot (90° - Φ)
Best answer will be marked as the BRANLIEST.
Answers
Answered by
4
LHS
(1 + tan²Ø)×cosØ×sinØ=sec²Ø × cosØsinØ
=( 1/cos²Ø) × cosØsinØ = (sinØ/cosØ)
= tanØ = cot(90°-Ø) = RHS
(1 + tan²Ø)×cosØ×sinØ=sec²Ø × cosØsinØ
=( 1/cos²Ø) × cosØsinØ = (sinØ/cosØ)
= tanØ = cot(90°-Ø) = RHS
sauveerdixit:
ok
whose answer should I mark as the branliest?
As you say
hi zaira wasim
ohh.... fake zaira wasim
Answered by
1
Hiiiiiiii mate
Your answer is
LHS
(1 + tan²Ø)×cosØ×sinØ
=sec²Ø × cosØsinØ
[ (1+tan²Ø)=sec²Ø]
=( 1/cos²Ø) × cosØsinØ
= (sinØ/cosØ)
= tanØ
= cot(90°-Ø)
= RHS
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