prove that (1+ tan^2 theta) cos theta cos (90°-theta)= cot (90°- theta)...plz solve it little fast...and a request that plz dont send unnecessary answers...
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Answered by
2
Answer:
plzzzzzzz mark this as the brainliest answer
Step-by-step explanation:
cos(90−A)=sin(A);
sin(90−A)=cos(A);
tan(90−A)=cot(A)
cot(A)=
sin(A)
cos(A)
LHS
tan(90−A)
cos(90−A)sin(90−A)
=
cot(A)
sin(A)cos(A)
cot(A)
sin(A)cos(A)
=
cos(A)
sin(A)cos(A)sin(A)
cos(A)
sin(A)cos(A)sin(A)
=sin(A)sin(A)=sin
2
(A)=LHS
RHS=sin
2
(A)
LHS=RHS
Hence Proved
Answered by
3
Answer:
hope it will help you
thank you
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