Question

prove that 1+ tan^2A/(1+secA)=secA.

Answer 1

Given Equation is (1 + tan^2A/(1 + secA)).

We know that tan^2A + 1 = sec^2A.

                        tan^2A = sec^2A - 1.

$1 + \frac{sec^2A - 1}{1 + secA}$

$1 + \frac{(secA + 1)(secA - 1)}{1 + secA}$

$1 + secA - 1$

secA.


LHS = RHS.


Hope this helps!

Answer 2

Hi

Please see the attached file!

Thanks