prove that (1+tan A) ² + (1-tan A) ² = 2sec²A
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Let's solve this by taking R.H.S. and L.H.S.
Take R.H.S. 2sec²A
Take left hand side of the equation (1+tanA)²+(1-tanA)²=2sec²A
L.H.S.= (1+tanA)²+(1-tanA)²= 1+tan²A+ 2tanA + 1 tan²A+2 tanA
=2+2 tan²A
=2+1 tan²A
=2 sec²A
Hence L.H.S. = R.H.S.
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