Prove that (1 + tan A – sec A) × (1 + tan A + sec A) = 2 tan A
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To prove:
(1 + tan A - sec A) × (1 + tan A + sec A) = 2 tan A
Proof:
LHS
(1 + tan A - sec A) × (1 + tan A + sec A)
...... Using (a+b) (a+b) = (a+b) ²
......... Multiply sec A × sec A
(1 + tan A) ² - sec ²A
....... Using (a+b) ² = a² + b² + 2ab
1 + tan² A + 2 tan A - sec² A
........ Using trigonometry identity 1 + tan² A = sec² A
sec² A + 2 tan A - sec² A
....... + sec² A and - sec² A gets cancelled because of + and - sign
2 tan A
Therefore LHS = RHS
Hence proved that (1 + tan A - sec A) × (1 + tan A + sec A) = 2 tan A
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