Math, asked by shushmitha21, 4 months ago

prove that (1+tan A - secA) (1+cotA+cosecA)=2​

Answers

Answered by sandy1816
0

(1 + tana - seca)(1 + cota + coseca) \\  \\  = ( \frac{cosa + sina - 1}{cosa} )( \frac{sina + cosa + 1}{sina} ) \\  \\  = \frac{( {cosa + sina})^{2} - 1 }{cosasina}  \\  \\  =  \frac{1 + 2sinacosa - 1}{sinacosa}  \\  \\  = 2

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